NECO-Mathematics-ANSWERS

 MATHS OBJ*

01-10: BCBEDDCCDC
11-20: DEBCBBDDEC
21-30: BCBCCBAEED
31-40: EBABEDCDBB
41-50: DDCECDCBAB
51-60: DDBCEACBBE

*2020 NECO MATHEMATICS ANSWERS*
========================================

THEORY
~~~~~~~~~

(1a)
x¹ y¹. x¹ y¹
A (6,5). B ( -2 ,7)

The equation of a straight line
y² - y¹/x² - x¹ = y-y/x¹-x¹

7-5/-2-6 = y-5/x-6
2/-8 = y-5/x-6
-1/4 = y-5/x-6
4(y-5)= -1(x-6)
4y-20= -x+6
4y+x=6+20
4y+x=26

(1b)
∫² (2x + 9)dx
-²
2x²/2+9x + c|²_¹
x² + 9x + c|²_¹
(2² + 9(2) + C) - ((-1)² + 9 (-1)+ c)
(4+18+c) - (1-9+C)
(22 + C) - (-8 + C)
22+C + 8 - C
=30.

(2a)
To calculate u; 18+5+12+u=52
35+u=52
u=52-32=17
u=17

To calculate v
6+5+12+v=35
23+v=35
v=35-23=12
v=12

To calculate w
w+18+17+6+5+12+12
=100
w+70=100
w=100+70=30
w=30

(2b)
at least two means =18+6+5+12=41
; 41 tourist travelled by at least two means of transportation.
========================================

(2a)
To calculate u; 18+5+12+u=52
35+u=52
u=52-32=17
u=17

To calculate v
6+5+12+v=35
23+v=35
v=35-23=12
v=12

To calculate w
w+18+17+6+5+12+12
=100
w+70=100
w=100+70=30
w=30

(2b)
at least two means =18+6+5+12=41
; 41 tourist travelled by at least two means of transportation.

========================================

(3a)
(i)median =6+6/2=12/2=6
(ii)median + range = 6+7=13
Range = highest value - lowest value = 10-3=7

(3b)
Pr(both pass)
=2/5*3/4=6/20=3/10.

========================================

(4a)
x²+3x-28=0
x²+7x-4x-28=0
x(x+7)-4(x+7)=0
(x-4)(x+7)=0
x-4=0 or x+7=0
x=0+4 or x=0-7
x=4 or -7

(4b)
8x/9 - 3x/2 =5/6 - x/1
L.c.m=54
6*8x-27*3x=9*5-54*x
48x-81x=45-54x
48x-81x+54x=45
21x/21=45/21
x=45/21=15/7=2⅐

========================================

(5a)
Let u = 4x³ - 2x + 4 ,
y = u³ , du/dx = 12x²-2,
dy/du=3u²

dy/dx= dy/du*du/dx
=3u²*12x²-2
=(36x² - 6) u²
Recall u=4x³ - 2x + 4
dy/dx= (36x² - 6) (4x³-2x + 4)²

(5b)
5/3(2-x) - (1-x)/2-x = 2/3
L.c.m= 3(2-x)
5-3(1-x) = 2(2-x)
5-3+3x=4-2x
2+3x=4-2x
3x+2x=4-2
5x/5=2/5
x=2/5

========================================

(6a)
Volume of a sphere = 9⅓ of its surface area 4/3 πr³=28/3*4πr²
4πr³/3*112πr²/3
3*4πr³=3*112πr²
12πr³=336πr²
Divide through by 12πr²
12πr³/12πr² = 336πr²/12πr²

r=28cm

(i)surface area =4πr²
=4*22/7*28cm*28cm
=98cm²

(ii) volume =4/3πr³
=4/3*22/7*28cm*28cm*28cm
=91989.33cm³ ≅ 91989cm³

(6b)
Log10 (3x-5)² - Log10 (4x-3)² =Log²⁵,¹⁰
(3x-5/4x-3)²=25
Square root both side
3x-5/4x-3=5/1
5(4x-3)=3x-5
20x-15=3x-5
20x-3x=-5+15
17x=10=x = 10/17

========================================

(7a)
(y,x)
(3,2)perpendicular to the line 3x + 5y = 10
3x + 5y =10
5y/5= -3x/5 +10/5
y=3x/5 + 2
m=3/5

The equation of a line y= y¹=1/m(x-x¹)
y-2= 1/⅗(x-3)
y-2=-5/3(x-3)
3(y-2)=-5(x-3)
3y-6= -5x + 15
3y= - 5x + 15 + 6
3y/3= -5x/3 + 21/3
y= -5x/3 + 7
Gradient = -5/3 intercept = 7

(7b)
Compound interest = p(1+R/100)n-p
=8000(1+5/100)³ - 8000
=8000(1+0.05)³ - 8000
=9261 - 8000
Compound interest= ₦1261

========================================

(8a)
Ta; a+8d=50 --------(1)
T12; a+11d=65---------(2)
Subtract equation (1) from (2)
a+11d-(a+8d)=65-50
a+11d-a-8d=15
11d-8d=15
3d/3=15/3
d=5

Substitute for d=5 in each equation (1)
a+8d=50
a+8(5)=50
a+40=50
a=50-40=10
Sn=n/2(2a+(n-1)d)
S70=70/2(2*10+(70-1)5)
=35(20+69*5)
=35*365=12,775

(8b)
V=t²-3t+2
d³/dt=v
d³/dt=t²-3t+2
v=6²-3(6)+2
=36-18+2
v=20mls

Recall; ds/dt=v
ds=vdt
∫ds=∫vdt
S=∫vdt
S=∫20dt
S=20t+c
Where c is constant.

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(10a)
Let daughter = x
Woman = 4x
In 5 years time ;
daughter = x + 5
Woman = 4x + 5

(4x + 5)² = (x + 5)² + 120.

(4x + 5 ) (4x + 5) = (x + 5) (x + 5)+ 120

16x² + 20x + 20x + 25= x²+5x+5x+25+120

16x²+40x+25= x²+10x+145

16x²-x²+40x-10x+25-145=0
15x²+30x-120=0
Divide through by 15;
15x²/15+30x/15-120/15=0/15

x² + 2x - 8= 0
x² + 4x - 2x - 8= 0
x(x+4) - 2 (x + 4) = 0
(x-2) (x+4)=0
x - 2= 0 or x+ 4= 0
x=2 or x=-4
x=2

The daughters age is 2years

(10b)
t=w+wy²/pz
t-w/1 * wy²/pz
10/y²/10 = pz(t-w)/w
y=√pz(t-w)/w
y=√5*10(9-3)/3
y=√5*10*6/2
=√100=10
;y=10

========================================

(11)
|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|Frequency|3|10-T|3T|8|2T+2|T+2|

(a)Ʃ+=50
3+10-T+3T+8+2T+2+T+2=50

3+10+8+2+2-T+3T+2T+T=50

25+5T=50
5T=50-20
5T/5=25/5
T=5

(11b)
|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|Frequency|3|5|15|8|12|7|

The frequency of the modal class is 15.

(11c)
Tabulate.
|Score|5-9|10-14|15-19|20-24|25-29|30-34|

|F|3|5|1|5|8|1|2|7|50

|X|7|12|17|22|27|32|

|FX|21|60|255|176|324|224|1060

|X-x̅|-14.2|-9.2|-4.2|0.8|5.8|10.8|

|(X-x̅)²|201.64|84.64|17.64|0.64|33.64|116.64|

F|(X-x̅)|604.92|423.2|264.6|5.12|403.68|816.48|2518

Mean (x̅) =Ʃfx/Ʃf=1060/50=21.2

Variance =Ʃf(x-x̅)²/Ʃf
=2518/50
=50.36

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(12a)
y=²-2x-3
Tabulate
|x|-2|-1|0|1|2|3|
|y|5|0|-3|-4|-3|0|

12b)
*[Check the Diagram below]*

(12c)
y=1-3x
|y|-2|-1|0|1|2|3|
|x|7|4|1|-2|-5|-8|

(12d)
(i)the root of the equation x² - 2x - 3= 1-3x are -3 and 1.6

(ii) the minimum value of y is - 4 and the corresponding value of x is 1

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Breaking: Abubakar Atiku Is Dead.

Posted by Kingzicoflexx 

September 12 at 11:18pm

 Physiotherapist, Abubakar Atiku was stabbed to death by phone thieves in Kano on Thursday night and has been reportedly buried, in Ringim local government, Jigawa State in accordance with Islamic rites. The deceased’s brother, Dr Idris Tijjani Shuaibu, while narrating how his brother met his untimely death, disclosed on Friday, that “the late Physiotherapist who recently graduated from School of Nursing, Birnin Kudu and yet to start practice was attacked close to the first gate, red bricks, along Gwarzo Road, Gwale local government area, Kano, around 10.00 pm on Thursday night, who is presently at Teaching Hospital added that “based on the information gathered, unfortunately, when he arrived his friend’s house, he was not around and he had to phone him to know his whereabouts to find out. Unknown to him, that he was been trailed by phone thieves, the deceased was subsequently attacked and he raised the alarm that led to the neighbours rushing to the scene, saw two of the attackers speed off on a motorcycle while the deceased was in a pool of blood. Dr Idris Tijjani Shuaibu, however, stated that his brother was immediately rushed to Murtala Muhammed Specialists Hospital where he died.

Sourced from: 9News

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Prevent Allergies and Asthma Attacks at Home

 Prevent Allergies and Asthma Attacks at Home

                    The Basics: Overview
If someone in your family has allergies or asthma, make your home a healthier place by getting rid of the things that can cause allergy symptoms or an asthma attack.

What can cause allergy symptoms or an asthma attack?
Things that can cause allergy symptoms are called allergens. Asthma attacks can be caused by irritants (things that can irritate the lungs) or allergens. Different people will react to different allergens and irritants.

Common causes of allergy symptoms and asthma attacks at home include:

Mold or dampness
Dust mites (tiny bugs that live in beds and carpets)
Pets with fur, including cats and dogs
Cockroaches (roaches and their droppings may cause asthma)
Mice, rats, and other rodents
Secondhand smoke
Wood smoke
Strong fragrances

Take Action!

Follow these steps to make your home a healthier place for people with allergies or asthma.

Find out what causes your allergy symptoms or asthma attacks.
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Keep allergens and irritants out of the bedroom.
Cover your mattresses and pillows in “dust proof” (or "allergen proof") covers.
Wash all your bedding in very hot water (at least 130 °F) once a week. Go to a laundromat if the water in your home doesn't get that hot.
Keep stuffed animals off the bed.
If you have pets that you are allergic to (like cats or dogs), keep them out of the bedroom.
If possible, remove all carpets. It’s easier to keep bare floors clean.
Control moisture to prevent mold.
Keep your home dry to prevent mold. Mold can start to grow in wet or damp places within just 1 or 2 days.

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When you take a shower, run the bathroom fan or open the window for at least 20 minutes afterward.
Check the humidity level in your home with a moisture or humidity meter (available at a hardware store).
Use a de-humidifier or air conditioner to keep the humidity level in your home below 60 percent. A humidity level between 30 and 50 percent is best.